(3/x-10)-(4x/x^2-100)=(4/x+10)

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Solution for (3/x-10)-(4x/x^2-100)=(4/x+10) equation: 


D( x )

x = 0

x^2 = 0

x = 0

x = 0

x^2 = 0

x^2 = 0

1*x^2 = 0 // : 1

x^2 = 0

x = 0

x in (-oo:0) U (0:+oo)

3/x-((4*x)/(x^2))-10+100 = 4/x+10 // - 4/x+10

3/x-((4*x)/(x^2))-(4/x)-10-10+100 = 0

3/x-4*x^-1-4*x^-1-10-10+100 = 0

-5*x^-1 = -80 // : -5

x^-1 = 16

-1 < 0

1/(x^1) = 16 // * x^1

1 = 16*x^1 // : 16

1/16 = x^1

x = 1/16

x = 1/16

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